Question

simplify your answer.
$(3x^2y + 1xy - 7xy^2) - (-5x^2y + 5xy + 6xy^2)$

Explanation:

Step1: Distribute the negative sign

$3x^2y + xy - 7xy^2 + 5x^2y - 5xy - 6xy^2$

Step2: Combine like $x^2y$ terms

$(3x^2y + 5x^2y) + xy - 7xy^2 - 5xy - 6xy^2 = 8x^2y + xy - 7xy^2 - 5xy - 6xy^2$

Step3: Combine like $xy$ terms

$8x^2y + (xy - 5xy) - 7xy^2 - 6xy^2 = 8x^2y - 4xy - 7xy^2 - 6xy^2$

Step4: Combine like $xy^2$ terms

$8x^2y - 4xy + (-7xy^2 - 6xy^2) = 8x^2y - 4xy - 13xy^2$

Answer:

$8x^2y - 4xy - 13xy^2$