QUESTION IMAGE
Question
simplify.
- ((n^4)^{\frac{3}{2}})
- ((a^8)^{\frac{3}{2}})
- ((64m^4)^{\frac{3}{2}})
- ((81p^4)^{\frac{3}{2}})
- ((49n^2)^{\frac{1}{2}})
- ((4k^4)^{\frac{3}{2}})
- ((64x^6)^{\frac{3}{2}}) (with some handwritten notes and calculations)
- ((9r^4)^{0.5}) (converted to ((9r^4)^{\frac{1}{2}}) with handwritten work)
- ((125n^6)^{\frac{5}{3}})
- ((27p^6)^{\frac{5}{3}}) (with handwritten calculations including calculator input notes)
- ((216r^9)^{\frac{1}{3}}) (with handwritten cube root work)
- ((16x^{12})^{\frac{5}{4}})
- ((81v^8)^{\frac{3}{4}})
- ((x^{16})^{\frac{5}{4}})
- (3b^{\frac{1}{2}} cdot b^{\frac{4}{3}})
Step1: Apply power rule $(x^a)^b=x^{a \cdot b}$
For each term, multiply exponents:
- $(n^4)^{\frac{3}{2}} = n^{4 \cdot \frac{3}{2}} = n^6$
- $(a^8)^{\frac{3}{2}} = a^{8 \cdot \frac{3}{2}} = a^{12}$
- $(64m^4)^{\frac{3}{2}} = 64^{\frac{3}{2}} \cdot m^{4 \cdot \frac{3}{2}} = (8^2)^{\frac{3}{2}} \cdot m^6 = 8^3 \cdot m^6 = 512m^6$
- $(81p^4)^{\frac{3}{2}} = 81^{\frac{3}{2}} \cdot p^{4 \cdot \frac{3}{2}} = (9^2)^{\frac{3}{2}} \cdot p^6 = 9^3 \cdot p^6 = 729p^6$
- $(49n^2)^{\frac{1}{2}} = 49^{\frac{1}{2}} \cdot n^{2 \cdot \frac{1}{2}} = 7n$
- $(4k^4)^{\frac{3}{2}} = 4^{\frac{3}{2}} \cdot k^{4 \cdot \frac{3}{2}} = (2^2)^{\frac{3}{2}} \cdot k^6 = 2^3 \cdot k^6 = 8k^6$
- $(64x^6)^{\frac{3}{2}} = 64^{\frac{3}{2}} \cdot x^{6 \cdot \frac{3}{2}} = (8^2)^{\frac{3}{2}} \cdot x^9 = 8^3 \cdot x^9 = 512x^9$
- $(9r^{-4})^{0.5} = (9r^{-4})^{\frac{1}{2}} = 9^{\frac{1}{2}} \cdot r^{-4 \cdot \frac{1}{2}} = 3r^{-2} = \frac{3}{r^2}$
- $(125n^6)^{\frac{5}{3}} = 125^{\frac{5}{3}} \cdot n^{6 \cdot \frac{5}{3}} = (5^3)^{\frac{5}{3}} \cdot n^{10} = 5^5 \cdot n^{10} = 3125n^{10}$
- $(27p^6)^{\frac{5}{3}} = 27^{\frac{5}{3}} \cdot p^{6 \cdot \frac{5}{3}} = (3^3)^{\frac{5}{3}} \cdot p^{10} = 3^5 \cdot p^{10} = 243p^{10}$
- $(216r^9)^{\frac{1}{3}} = 216^{\frac{1}{3}} \cdot r^{9 \cdot \frac{1}{3}} = (6^3)^{\frac{1}{3}} \cdot r^3 = 6r^3$
- $(16x^{12})^{\frac{5}{4}} = 16^{\frac{5}{4}} \cdot x^{12 \cdot \frac{5}{4}} = (2^4)^{\frac{5}{4}} \cdot x^{15} = 2^5 \cdot x^{15} = 32x^{15}$
- $(81v^8)^{\frac{3}{4}} = 81^{\frac{3}{4}} \cdot v^{8 \cdot \frac{3}{4}} = (3^4)^{\frac{3}{4}} \cdot v^6 = 3^3 \cdot v^6 = 27v^6$
- $(x^{16})^{\frac{5}{4}} = x^{16 \cdot \frac{5}{4}} = x^{20}$
- Apply product rule $x^a \cdot x^b = x^{a+b}$:
$3b^{\frac{1}{2}} \cdot b^{\frac{4}{3}} = 3b^{\frac{1}{2}+\frac{4}{3}} = 3b^{\frac{3+8}{6}} = 3b^{\frac{11}{6}}$
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- $n^6$
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