Question

short - answer: two charged objects are moved farther apart. what happens to the electric force between them? explain using coulombs law. your answer

Explanation:

Coulomb's Law states that the electric force \( F \) between two charged objects is given by \( F=\frac{kq_1q_2}{r^{2}} \), where \( k \) is a constant, \( q_1 \) and \( q_2 \) are the charges of the two objects, and \( r \) is the distance between them. When the two charged objects are moved farther apart, \( r \) increases. Since \( F \) is inversely proportional to \( r^{2} \) (\( F\propto\frac{1}{r^{2}} \)), as \( r \) gets larger, the value of \( \frac{1}{r^{2}} \) gets smaller. So the electric force between them decreases.

Answer:

The electric force between them decreases. According to Coulomb's Law \( F = \frac{kq_1q_2}{r^{2}} \), when \( r \) (the distance between the charged objects) increases, since \( F\propto\frac{1}{r^{2}} \), the electric force \( F \) becomes smaller.