Question

seventeen percent of u.s. employees who are late for work blame oversleeping. you randomly select four u.s. employees who are late for work and ask them whether they blame oversleeping. the random variable represents the number of u.s. employees who are late for work and blame oversleeping.

find the mean of the binomial distribution.
\\(\mu = 0.68\\) (round to the nearest hundredth as needed.)

find the variance of the binomial distribution.
\\(\sigma^2 = \\) (round to the nearest hundredth as needed.)

Explanation:

Identify binomial parameters

$$
LATEXBLOCK0
$$

Calculate the variance

$$
LATEXBLOCK1
$$

Round to the nearest hundredth

$$ \sigma^2 \approx 0.56 $$

Answer:

Find the variance of the binomial distribution.

\(\sigma^2 =\) <blank>0.56</blank> (Round to the nearest hundredth as needed.)