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7. seven guests are arriving for dinner. how many possible orders can t…

Question

  1. seven guests are arriving for dinner. how many possible orders can they arrive in?

5,040!
5!
7!
49!

Explanation:

Step1: Recall Permutation of n Objects

The number of permutations (orders) of \( n \) distinct objects is given by \( n! \) (n factorial), where \( n! = n\times(n - 1)\times(n - 2)\times\cdots\times1 \). Here, we have 7 guests, so we need to find the number of permutations of 7 objects.

Step2: Apply the Factorial Formula

For \( n = 7 \), the number of possible orders is \( 7! \). Calculating \( 7! \): \( 7! = 7\times6\times5\times4\times3\times2\times1 = 5040 \), but the form of the answer is in terms of factorial, so the number of possible orders is \( 7! \).

Answer:

\( 7! \) (The option corresponding to \( 7! \))