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the set of life spans of an appliance is normally distributed with a me…

Question

the set of life spans of an appliance is normally distributed with a mean \\(\mu = 48\\) months and a standard deviation \\(\sigma = 8\\) months. what is the z-score of an appliance that stopped working at 64 months?

-2
-1
1
2

Explanation:

Identify the given parameters

$$ \mu = 48,\quad \sigma = 8,\quad x = 64 $$

Apply the z-score formula

$$ z = \frac{x - \mu}{\sigma} $$

Calculate the final value

$$ z = \frac{64 - 48}{8} = \frac{16}{8} = 2 $$

Answer:

  • (A) \(-2\)
  • (B) \(-1\)
  • (C) \(1\)
  • (D) \(2\) (Correct answer)