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a set of data items is normally distributed with a mean of 80 and a sta…

Question

a set of data items is normally distributed with a mean of 80 and a standard deviation of 8. convert 88 to a z - score.

( z_{88}=square )
(type an integer or a decimal.)

Explanation:

Step1: Recall the z - score formula

The formula for the z - score is \(z=\frac{x-\mu}{\sigma}\), where \(x\) is the data item, \(\mu\) is the mean, and \(\sigma\) is the standard deviation.

Step2: Substitute the given values into the formula

Given \(x = 88\), \(\mu=80\), and \(\sigma = 8\). Then \(z=\frac{88 - 80}{8}\).

Step3: Calculate the value

First, calculate the numerator: \(88-80 = 8\). Then \(\frac{8}{8}=1\).

Answer:

\(1\)