Question

a series circuit contains three 2 ω resistors and a 6 ω resistor. the current in each resistor is 4.0 a. what is the voltage of the battery in the circuit?
○ 2.0 v
○ 3.0 v
○ 32 v
○ 48 v

Explanation:

Step1: Calculate total resistance in series

In a series circuit, total resistance \( R_{total} \) is the sum of individual resistances. There are three \( 2\,\Omega \) resistors and one \( 6\,\Omega \) resistor. So, \( R_{total}=3\times2 + 6\).
\( R_{total}=6 + 6 = 12\,\Omega \)

Step2: Use Ohm's Law to find voltage

Ohm's Law is \( V = I\times R \), where \( I = 4.0\,\text{A} \) (current) and \( R = R_{total}=12\,\Omega \).
\( V = 4.0\times12 \)
\( V = 48\,\text{V} \)

Answer:

48 V (corresponding to the option "48 V")