Question

select the equation that will correctly show that nearly 1140 w of power is expended when a 700 - n barbell is lifted 2.6 m above the floor in 1.6 s.
$p=\frac{w}{t}=\frac{fd}{t^2}$
$p=\frac{w}{t}=\frac{2fd}{3t}$
$p=\frac{w}{t}=\frac{2fd}{t}$
$p=\frac{w}{t}=\frac{fd}{t}$

Explanation:

Step1: Recall power formula

Power $P=\frac{W}{t}$, where $W$ is work - done and $t$ is time. Work - done $W = Fd$, where $F$ is force and $d$ is distance.

Step2: Substitute $W = Fd$ into power formula

Substituting $W = Fd$ into $P=\frac{W}{t}$, we get $P=\frac{W}{t}=\frac{Fd}{t}$.

Answer:

$P=\frac{W}{t}=\frac{Fd}{t}$ (the first option)