Question

select the correct answer. robert, a stuntman, projects himself from a height of 50.0 meters in a horizontal direction. he safely lands at a horizontal distance of 100.0 meters. calculate the horizontal velocity with which robert projected himself. a. 4.90 meters/second b. 31.30 meters/second c. 10.20 meters/second d. 12.20 meters/second

Explanation:

Step1: Find fall time (vertical motion)

$t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2 \times 50.0}{9.8}} \approx 3.194\ \text{s}$

Step2: Calculate horizontal velocity

$v = \frac{x}{t} = \frac{100.0}{3.194} \approx 31.30\ \text{m/s}$

Answer:

B. 31.30 meters/second