QUESTION IMAGE
Question
select the correct answer from each drop - down menu.
a ray of light is reflected from a mirror such that the reflected ray is perpendicular to the original ray, as shown in the diagram.
the equation of the reflected ray is ( y + x = 6 ). the point
next
Step1: Check if the point lies on the line \(y + x=6\)
For the point \((2,4)\):
Substitute \(x = 2\) and \(y = 4\) into the equation \(y+x\).
\(y+x=4 + 2=6\)
Step2: Check for the point \((4,2)\)
Substitute \(x = 4\) and \(y = 2\) into the equation \(y+x\).
\(y+x=2+4 = 6\)
Step3: Check for the point \((8,-2)\)
Substitute \(x = 8\) and \(y=-2\) into the equation \(y+x\).
\(y+x=-2 + 8=6\)
Step4: Check for the point \((-2,-8)\)
Substitute \(x=-2\) and \(y =-8\) into the equation \(y+x\).
\(y+x=-8+( - 2)=-10
eq6\)
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\((-2,-8)\)