QUESTION IMAGE
Question
select all of the statements that must be true if m∠4 = m∠6.
image of angle diagram with lines a, b, c and angles 1-8
a. a ⊥ b
b. m∠4 = 90
c. m∠2 ≠ m∠8
d. m∠3 ≠ m∠4
e. m∠3 = m∠7
Step1: Analyze ∠4 and ∠6 relationship
∠4 and ∠6 are same - side interior angles. If \(m\angle4 = m\angle6\), and for same - side interior angles, when \(m\angle4=m\angle6\), since same - side interior angles are supplementary (i.e., \(m\angle4 + m\angle6=180^{\circ}\)) in general, if \(m\angle4 = m\angle6\), then \(m\angle4=m\angle6 = 90^{\circ}\). So lines \(b\) and \(c\) are parallel? Wait, no, ∠4 and ∠6 are formed by transversal \(a\) cutting \(b\) and \(c\). Wait, actually, ∠4 and ∠6: ∠4 and ∠5 are supplementary (linear pair), ∠5 and ∠6 are vertical angles? No, ∠4 and ∠6: let's look at the lines. Line \(a\) is a transversal, lines \(b\) and \(c\) are two lines. ∠4 and ∠6: if \(m\angle4 = m\angle6\), and ∠4 + ∠6 = 180° (same - side interior angles), then \(2m\angle4=180^{\circ}\), so \(m\angle4 = 90^{\circ}\), so line \(a\) is perpendicular to lines \(b\) and \(c\)? Wait, no, ∠4 and ∠6: if \(m\angle4=m\angle6\) and they are same - side interior angles, then they must be right angles. So \(a\perp b\) and \(a\perp c\), so \(b\parallel c\) (if two lines are perpendicular to the same transversal, they are parallel). Now let's check each option:
- Option A: \(a\perp b\). Since \(m\angle4 = 90^{\circ}\) (because \(m\angle4=m\angle6\) and \(m\angle4 + m\angle6 = 180^{\circ}\)), so the angle between \(a\) and \(b\) is \(90^{\circ}\), so \(a\perp b\). This is true.
- Option B: \(m\angle4 = 90^{\circ}\). As we saw, since \(m\angle4=m\angle6\) and \(m\angle4 + m\angle6=180^{\circ}\), solving \(2m\angle4 = 180^{\circ}\) gives \(m\angle4 = 90^{\circ}\). This is true.
- Option C: \(m\angle2
eq m\angle8\). ∠2 and ∠8: ∠2 and ∠4 are vertical angles? No, ∠2 and ∠3 are vertical angles, ∠4 and ∠1 are vertical angles. Wait, ∠2 and ∠8: ∠2 and ∠4 are supplementary (linear pair), ∠4 = 90°, so ∠2 = 90°. ∠8 and ∠6 are vertical angles, ∠6 = 90°, so ∠8 = 90°. So \(m\angle2=m\angle8 = 90^{\circ}\), so this statement is false.
- Option D: \(m\angle3
eq m\angle4\). ∠3 and ∠4: they are adjacent angles forming a linear pair? Wait, ∠3 and ∠4: if \(a\perp b\), then ∠3 and ∠4 are both 90°? Wait, no, ∠3 and ∠4: if \(a\perp b\), then the angle between \(a\) and \(b\) is 90°, so ∠3 and ∠4 are complementary? Wait, no, ∠3 + ∠4=180°? No, ∠3 and ∠4: if \(a\perp b\), then ∠3 and ∠4 are both 90°? Wait, no, in the diagram, ∠3 and ∠4 are adjacent angles at the intersection of \(a\) and \(b\). If \(a\perp b\), then ∠3 = ∠4 = 90°, so \(m\angle3=m\angle4\), so this statement is false.
- Option E: \(m\angle3 = m\angle7\). ∠3 and ∠7: ∠3 and ∠4 are 90° (if \(a\perp b\)), ∠7 and ∠6 are vertical angles, ∠6 = 90°, so ∠7 = 90°. ∠3 = 90°, so \(m\angle3=m\angle7\). This is true. Wait, but let's re - examine. If \(a\perp b\) and \(a\perp c\), then \(b\parallel c\) (corresponding angles are equal, since both are 90° with transversal \(a\)). Then ∠3 and ∠7: ∠3 and ∠5 are equal (alternate interior angles, since \(b\parallel c\)), and ∠5 and ∠7 are vertical angles, so ∠3 = ∠5 = ∠7. So \(m\angle3 = m\angle7\) is true. Wait, but earlier when we thought about option D, we made a mistake. Wait, ∠3 and ∠4: if \(a\perp b\), then ∠3 and ∠4 are both 90°? Wait, no, ∠3 and ∠4: in the intersection of \(a\) and \(b\), ∠3 and ∠4 are adjacent angles. If \(a\perp b\), then the four angles formed are all 90°, so ∠3 = ∠4 = 90°, so option D is false.
Wait, let's start over. Given \(m\angle4=m\angle6\). ∠4 and ∠6 are same - side interior angles (formed by transversal \(a\) cutting lines \(b\) and \(c\)). The same - side interior angles theorem states that if two lines are parallel, then same - side interi…
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A. \(a \perp b\), B. \(m\angle4 = 90\), E. \(m\angle3 = m\angle7\)