Question

select all the correct answers. two buses leave school moving in opposite directions. after 15 minutes, they are both 10 miles away from the school. which statements correctly describe the motion of the buses? the velocity of the buses is equal. the average speed of the buses is equal. the average speed of the buses is not equal. the velocity of the buses is not equal. both buses move with constant velocity the entire trip.

Explanation:

Step1: Recall the definitions of speed and velocity

Speed is a scalar quantity (only magnitude), calculated as \(s=\frac{d}{t}\). Velocity is a vector quantity (magnitude and direction).

Step2: Calculate the average speed

Given \(d = 10\) miles and \(t=15\) minutes \(=\frac{15}{60}=\frac{1}{4}\) hours.
The average speed formula \(s=\frac{d}{t}\). For both buses, \(s=\frac{10}{\frac{1}{4}} = 40\) miles per hour. So the average speed of the buses is equal.

Step3: Analyze the velocity

Since the buses are moving in opposite directions, the direction part of the velocity (a vector) is different. So the velocity of the buses is not equal.

Answer:

The average speed of the buses is equal. ; The velocity of the buses is not equal.