the segments are tangents to the circle. find the perimeter of jlno.
the perimeter of the polygon is
(simplify your answer.)

Question

Accepted Answer

# Explanation:
## Step1: Use the property of tangent segments
If two tangent segments are drawn from the same external point to a circle, then the two tangent segments are congruent.
So, $JK = JR = 3$, $LK=LM = 4$, $MN = NP=2$, $QR = QP$.
Since $QR = 7$, then $QP = 7$.

## Step2: Calculate the perimeter of $JLNQ$
The perimeter $P$ of $JLNQ$ is $P=JK + LK+LM + MN+NP+QP+QR+JR$
Substitute the values:
$$
\begin{align*}
P&=(3 + 3)+(4 + 4)+(2+2)+(7 + 7)\
&=6 + 8+4 + 14
\end{align*}
$$

# Answer:
$32$

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QUESTION IMAGE

Question

Explanation:

Step1: Use the property of tangent segments

Step2: Calculate the perimeter of \(JLNQ\)

Answer: