Question

segments rt and su are diameters of circle o. what is ( moverarc{srt} )? ( 282^circ ) ( 258^circ ) ( 274^circ ) ( 266^circ )

Explanation:

Step1: Calculate the measure of arc \( SR \)

Since \( \angle SOR = 94^{\circ} \), the measure of arc \( SR \) is \( 94^{\circ} \) (central angle theorem).

Step2: Calculate the measure of arc \( RT \)

Since \( RT \) is a diameter, the measure of arc \( RT \) is \( 180^{\circ} \) (semicircle).

Step3: Calculate the measure of arc \( SRT \)

The measure of arc \( SRT \) is the sum of the measures of arc \( SR \) and arc \( RT \). So, \( m\overarc{SRT}=94^{\circ}+180^{\circ} = 274^{\circ} \)

Answer:

\( 274^{\circ} \)