Question

7.4
score: 10/17 answered: 10/17
question 11
how many different photographs are possible if five children sit in the front row and three adults sit in
the back row?
question help: video ebook written example

Explanation:

Step1: Calculate permutations for children

The number of permutations of \( n \) distinct objects is \( n! \). For 5 children, the number of ways they can arrange themselves is \( 5! \).
\( 5! = 5\times4\times3\times2\times1 = 120 \)

Step2: Calculate permutations for adults

For 3 adults, the number of ways they can arrange themselves is \( 3! \).
\( 3! = 3\times2\times1 = 6 \)

Step3: Find total number of photographs

To find the total number of different photographs, we multiply the number of arrangements of children and adults (by the multiplication principle of counting).
Total arrangements \( = 5! \times 3! = 120\times6 = 720 \)

Answer:

720