Question

science 14
calculating work

1. a force of 6.0 n is needed to push a sled 15 m. calculate the amount of work done.
2. a simple machine uses a force of 26 n force to move an object 3.0 m. calculate the

amount of work done.
name

Explanation:

Problem 1

Step1: Recall the work formula

The formula for work is \( W = F \times d \), where \( W \) is work, \( F \) is force, and \( d \) is distance.

Step2: Substitute values

Given \( F = 6.0 \, \text{N} \) and \( d = 15 \, \text{m} \), substitute into the formula: \( W = 6.0 \, \text{N} \times 15 \, \text{m} \)

Step3: Calculate the result

\( 6.0 \times 15 = 90 \), so \( W = 90 \, \text{J} \) (since \( 1 \, \text{N·m} = 1 \, \text{J} \))

Step1: Recall the work formula

The formula for work is \( W = F \times d \), where \( W \) is work, \( F \) is force, and \( d \) is distance.

Step2: Substitute values

Given \( F = 26 \, \text{N} \) and \( d = 3.0 \, \text{m} \), substitute into the formula: \( W = 26 \, \text{N} \times 3.0 \, \text{m} \)

Step3: Calculate the result

\( 26 \times 3.0 = 78 \), so \( W = 78 \, \text{J} \) (since \( 1 \, \text{N·m} = 1 \, \text{J} \))

Answer:

The work done is \( 90 \, \text{J} \)

Problem 2