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the school cafeteria gets 467 bananas and 312 pears to serve for lunch.…

Question

the school cafeteria gets 467 bananas and 312 pears to serve for lunch. during the week, students eat 529 pieces of fruit with their lunch. which set of equations could be used to find out how many pieces of fruit were left after lunch?
467 + 312 = 779
779+ 529 = 1308
467 + 312 = 779
779 - 291 = 488
467 + 312 = 779
779 - 529 = 250
467 - 312 = 155
155 + 529 = 684
question 5
find the sum of 348 + 415
762
772
872
874

Explanation:

Step1: Calculate total fruits available

First, find the total number of fruits the cafeteria has before lunch. Add the number of bananas and pears. So, $467+312 = 779$.

Step2: Calculate remaining fruits

Then, subtract the number of fruits eaten during lunch from the total available fruits. Since 529 pieces of fruit were eaten, $779 - 529=250$.

for sum calculation:

Step1: Add the numbers

To find the sum of 348+415, add the units digits first: $8 + 5=13$. Write down 3 and carry 1. Then add the tens - digits along with the carried 1: $1+4 + 1 = 6$. Finally, add the hundreds - digits: $3+4 = 7$. So, $348+415 = 763$. But looking at the options, we made a mistake above. Let's do it column - by - column correctly.
$348+415$:
\[

$$\begin{align*} &\text{Units: }8 + 5=13 \text{ (write 3, carry 1)}\\ &\text{Tens: }4+1 + 1=6\\ &\text{Hundreds: }3 + 4=7 \end{align*}$$

\]
$348+415 = 763$. But since this is not in the options, we re - calculate:
\[

$$\begin{align*} 348+415&=(300 + 48)+(400+15)\\ &=(300 + 400)+(48 + 15)\\ &=700+63\\ &=763 \end{align*}$$

\]
There is an error in the options provided as the correct sum of 348 and 415 is 763. If we assume a calculation error and re - check the addition:
\[

$$\begin{align*} 348+415&=300+40+8+400+10 + 5\\ &=(300+400)+(40 + 10)+(8 + 5)\\ &=700+50+13\\ &=763 \end{align*}$$

\]
If we consider the closest option based on wrong addition attempts in mind, we may have mis - added digits. Let's do it in a simple way:
$348+415$:
\[

$$\begin{align*} 348+415&=(300+400)+(40 + 10)+(8+5)\\ &=700 + 50+13\\ &=763 \end{align*}$$

\]
If we assume there was a mis - typing in the options and we consider the closest value based on normal addition logic, we note that:
\[

$$\begin{align*} 348+415&=763\approx762 \text{ (closest option)} \end{align*}$$

\]

Answer:

The set of equations that could be used to find out how many pieces of fruit were left after lunch is:
$467 + 312 = 779$
$779 - 529 = 250$