Question

a sample of gas at a constant pressure initially has a temperature of 800.0 k with a volume of 4.50 l. the temperature changes to 569.3 k. calculate the final volume (in l). answer: l

Explanation:

Step1: Identify the gas law

At constant pressure, Charles's law applies: $\frac{V_1}{T_1}=\frac{V_2}{T_2}$.

Step2: Rearrange the formula for $V_2$

$V_2=\frac{V_1\times T_2}{T_1}$.

Step3: Substitute the given values

$V_1 = 4.50\ L$, $T_1=800.0\ K$, $T_2 = 569.3\ K$.
$V_2=\frac{4.50\times569.3}{800.0}$.

Step4: Calculate the value

$V_2=\frac{2561.85}{800.0}=3.2023125\ L$.

Answer:

$3.20\ L$ (rounded to three significant figures)