Question

samir bicycles 2.5 kilometers west to get from his house to school. after school, he bicycles 6.9 kilometers north to his friend reagans house. how far is samirs house from reagans house, measured in a straight line? if necessary, round to the nearest tenth. kilometers submit

Explanation:

Step1: Apply Pythagorean theorem

Let \(a = 2.5\) (west - east distance) and \(b=6.9\) (north - south distance). The distance \(d\) between Samir's house and Reagan's house is given by \(d=\sqrt{a^{2}+b^{2}}\).

Step2: Calculate \(a^{2}\) and \(b^{2}\)

\(a^{2}=(2.5)^{2}=6.25\), \(b^{2}=(6.9)^{2}=47.61\).

Step3: Sum \(a^{2}\) and \(b^{2}\)

\(a^{2}+b^{2}=6.25 + 47.61=53.86\).

Step4: Take the square - root

\(d=\sqrt{53.86}\approx7.3\)

Answer:

\(7.3\)