Question

for the same function func1, what will be printed when we run the following code?
def func1(x, y, z = 2):
if x - y < z:
return (x + y) * z
else:
return (x + y) / z
a = 2
b = 4
result = func1(a,b,3)
result = func1(b,a)
print(result)

Explanation:

Step1: Analyze the first function call

When result = func1(a,b,3) is executed, x = 2, y = 4, z = 3. Calculate x - y = 2 - 4=-2. Since -2<3, return (x + y)z=(2 + 4)3 = 18. But then result = func1(b,a) is executed.

Step2: Analyze the second function call

When result = func1(b,a) is executed, x = 4, y = 2, z takes the default value 2. Calculate x - y=4 - 2 = 2. Since 2 is not less than 2 (the condition x - y < z is False), return (x + y)/z=(4 + 2)/2=3.

Answer:

B. 3.0