Question

1. sally and ray work together on an assignment. they have broken down the work into of the same size. sally works at 2 times the speed of ray but has 5 pieces of work to dcanother subject. this problem can be represented by the following system of equations: 6b write down the solution to the system of equations as an ordered pair (x, y). (x, y) = 3, 1 (x, y) = 3, 1 (x, y) = (3, 1) 3 keep it up! 6c how many parts of the assignment did sally do? sallys contribution = 1 parts 3 well on track! 6d how many parts of the assignment did ray do? rays contribution = enter your next step here parts

Explanation:

Step1: Analyze the system's solution

From 6b, the solution to the system of equations (representing their work) is \((x, y) = (3, 1)\). Typically, we can assume \(x\) and \(y\) represent Sally's and Ray's work (or vice - versa, but let's check the context). Wait, in 6c, Sally's contribution was 1? Wait, maybe I mixed up. Wait, the problem says Sally works at 2 times the speed of Ray. Let's re - evaluate. Wait, the system of equations' solution is \((3,1)\). Let's assume that the total work is broken into parts, and from the solution, if we consider the variables: maybe \(x\) is Ray's work and \(y\) is Sally's? No, in 6c, Sally's contribution was 1? Wait, no, maybe the correct mapping is that from the solution \((x,y)=(3,1)\), if Sally has more speed (2 times Ray's), maybe Ray's work is 1 and Sally's is 3? Wait, the 6c answer was wrong? No, the 6c has a green check, so maybe the variables are defined as Sally's work is \(y\) and Ray's is \(x\). Wait, no, let's think again. The system of equations' solution is \((3,1)\). If we consider that the total work parts and their speeds, but from the 6c, Sally's contribution is 1? That seems conflicting. Wait, maybe the initial problem (not fully shown) has a system where, for example, let's say the total number of parts is \(x + y\) (or some relation), and from the solution \((3,1)\), if in 6c Sally's contribution is 1, then Ray's contribution should be 3? Wait, the 6c answer has a green check, so maybe there was a mix - up. Wait, no, looking at the 6d: we need to find Ray's contribution. From the solution of the system \((x,y)=(3,1)\), if we assume that \(x\) is Ray's work and \(y\) is Sally's (or vice - versa, but let's check the 6c: Sally's contribution is 1, so \(y = 1\), then \(x=3\) would be Ray's. So Ray's contribution is 3.

Step2: Confirm with the solution

The solution to the system of equations is \((x,y)=(3,1)\). If we take \(x\) as Ray's work (since Sally has more speed, but maybe the variables are assigned as Ray's work is \(x\) and Sally's is \(y\), or maybe the other way, but from 6c's answer (Sally's contribution = 1), then \(y = 1\) (Sally's work) and \(x = 3\) (Ray's work). So Ray's contribution is 3.

Answer:

3