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2. sales the table shows the sales of a health and beauty supply compan…

Question

  1. sales the table shows the sales of a health and beauty supply company in millions of dollars, for several years. let x be the number of years since 2010.
year20112012201320142015
sales12.219.129.437.349.7

a. write the equation for the best fit line for the data
b. find and interpret the correlation coefficient

Explanation:

Step1: Define Variables

Let \( x \) be years since 2010, so for 2011, \( x = 1 \); 2012, \( x = 2 \); 2013, \( x = 3 \); 2014, \( x = 4 \); 2015, \( x = 5 \). Sales \( y \) (in millions): \( (1, 12.2), (2, 19.1), (3, 29.4), (4, 37.3), (5, 49.7) \).

Step2: Calculate Mean of \( x \) and \( y \)

\( \bar{x} = \frac{1 + 2 + 3 + 4 + 5}{5} = 3 \)
\( \bar{y} = \frac{12.2 + 19.1 + 29.4 + 37.3 + 49.7}{5} = \frac{147.7}{5} = 29.54 \)

Step3: Calculate Slope (\( m \)) of Best - Fit Line

\( m=\frac{\sum_{i = 1}^{n}(x_i-\bar{x})(y_i - \bar{y})}{\sum_{i = 1}^{n}(x_i-\bar{x})^2} \)
First, calculate \( (x_i-\bar{x})(y_i - \bar{y}) \) and \( (x_i-\bar{x})^2 \) for each \( i \):

  • For \( i = 1 \): \( (1 - 3)(12.2 - 29.54)=(-2)(-17.34) = 34.68 \); \( (1 - 3)^2=4 \)
  • For \( i = 2 \): \( (2 - 3)(19.1 - 29.54)=(-1)(-10.44) = 10.44 \); \( (2 - 3)^2 = 1 \)
  • For \( i = 3 \): \( (3 - 3)(29.4 - 29.54)=(0)(-0.14)=0 \); \( (3 - 3)^2 = 0 \)
  • For \( i = 4 \): \( (4 - 3)(37.3 - 29.54)=(1)(7.76)=7.76 \); \( (4 - 3)^2 = 1 \)
  • For \( i = 5 \): \( (5 - 3)(49.7 - 29.54)=(2)(20.16)=40.32 \); \( (5 - 3)^2 = 4 \)

\( \sum(x_i-\bar{x})(y_i - \bar{y})=34.68 + 10.44+0 + 7.76 + 40.32=93.2 \)
\( \sum(x_i-\bar{x})^2=4 + 1+0 + 1+4 = 10 \)
\( m=\frac{93.2}{10}=9.32 \)

Step4: Calculate Intercept (\( b \)) of Best - Fit Line

Using \( y=mx + b \) and \( \bar{y}=m\bar{x}+b \)
\( 29.54=9.32\times3 + b \)
\( 29.54 = 27.96 + b \)
\( b=29.54 - 27.96 = 1.58 \)
So the best - fit line equation is \( y = 9.32x+1.58 \)

Step5: Calculate Correlation Coefficient (\( r \))

\( r=\frac{\sum(x_i - \bar{x})(y_i - \bar{y})}{\sqrt{\sum(x_i - \bar{x})^2\sum(y_i - \bar{y})^2}} \)
First, calculate \( \sum(y_i - \bar{y})^2 \):

  • For \( i = 1 \): \( (12.2 - 29.54)^2=(-17.34)^2 = 300.6756 \)
  • For \( i = 2 \): \( (19.1 - 29.54)^2=(-10.44)^2 = 108.9936 \)
  • For \( i = 3 \): \( (29.4 - 29.54)^2=(-0.14)^2 = 0.0196 \)
  • For \( i = 4 \): \( (37.3 - 29.54)^2=(7.76)^2 = 60.2176 \)
  • For \( i = 5 \): \( (49.7 - 29.54)^2=(20.16)^2 = 406.4256 \)

\( \sum(y_i - \bar{y})^2=300.6756+108.9936 + 0.0196+60.2176+406.4256 = 876.332 \)
\( r=\frac{93.2}{\sqrt{10\times876.332}}=\frac{93.2}{\sqrt{8763.32}}\approx\frac{93.2}{93.61}\approx0.995 \)
Interpretation: \( r\approx0.995 \) is close to 1, indicating a strong positive linear relationship between years since 2010 and sales.

Answer:

a. The equation of the best - fit line is \( \boldsymbol{y = 9.32x + 1.58} \)
b. The correlation coefficient \( r\approx\boldsymbol{0.995} \), which indicates a very strong positive linear association between the number of years since 2010 and the company's sales (as \( r \) is close to 1, the linear relationship between \( x \) and \( y \) is very strong).