Question

a rocket is fired upward with an initial velocity of 35 m/s. find the rockets maximum altitude. it will never leave the earth. 1.8 m 62.5 m 63 m

Explanation:

Step1: Identify the relevant kinematic - equation

The kinematic equation $v^{2}=v_{0}^{2}-2gh$ is used, where $v = 0$ at maximum altitude, $v_{0}=35$ m/s, and $g = 9.8$ m/s².

Step2: Rearrange the equation to solve for $h$

From $v^{2}=v_{0}^{2}-2gh$, we get $h=\frac{v_{0}^{2}-v^{2}}{2g}$. Substituting $v = 0$ and $v_{0}=35$ m/s, $g = 9.8$ m/s², we have $h=\frac{35^{2}-0^{2}}{2\times9.8}$.

Step3: Calculate the value of $h$

$h=\frac{1225}{19.6}=62.5$ m.

Answer:

C. 62.5 m