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right triangle trigonometry - sohcahtoa right triangle trigonometry rel…

Question

right triangle trigonometry - sohcahtoa
right triangle trigonometry relates the sides of a right triangle to the angle measures of the two acute angles.
calculate the value for x.
answer (round to nearest degree): x = □

Explanation:

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Answer:

}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0