QUESTION IMAGE
Question
right triangle trigonometry - sohcahtoa
right triangle trigonometry relates the sides of a right triangle to the angle measures of the two acute angles.
calculate the value for x.
answer (round to nearest degree): x = □
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}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0.35)\approx20.5^{\circ}\approx21^{\circ}$ (wrong). $\sin(x)=\frac{14}{40}=0.35$, $x=\sin^{-1}(0