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rewrite the following without an exponent. $9^{-2}$

Question

rewrite the following without an exponent.
$9^{-2}$

Explanation:

Step1: Recall negative exponent rule

The negative exponent rule states that \( a^{-n}=\frac{1}{a^{n}} \) for any non - zero number \( a \) and positive integer \( n \). For \( 9^{-2} \), here \( a = 9 \) and \( n=2 \), so we can rewrite \( 9^{-2} \) as \( \frac{1}{9^{2}} \).

Step2: Calculate \( 9^{2} \)

We know that \( 9^{2}=9\times9 = 81 \). So \( \frac{1}{9^{2}}=\frac{1}{81} \).

Answer:

\(\frac{1}{81}\)