Question

rewrite the following algebraic expression as an equivalent expression in its most simplified form.

$(x + 2) - (8 - x) = \square$

basic

7 8 9 ÷ x y $x^2$ $\sqrt{\square}$
4 5 6 × $\frac{\square}{\square}$ $x\frac{\square}{\square}$ $x^{\square}$ $x_{\square}$
1 2 3 − < > $\pm$ $$
0 . , + % $\circ$ : $(\square)$
$\blacktriangleleft$ $\blacktriangleright$ $\boldsymbol{\times}$ = $|\square|$ $\pi$ $\infty$

Explanation:

Step1: Remove parentheses

To simplify \((x + 2) - (8 - x)\), we first distribute the negative sign to the terms inside the second parentheses. This gives us \(x + 2 - 8 + x\).

Step2: Combine like terms

Next, we combine the \(x\)-terms and the constant terms. The \(x\)-terms are \(x\) and \(x\), so \(x + x = 2x\). The constant terms are \(2\) and \(-8\), so \(2 - 8 = -6\). Combining these results, we get \(2x - 6\).

Answer:

\(2x - 6\)