QUESTION IMAGE
Question
review the graph
which statement accurately describes the vector shown?
○ magnitude of \\(\sqrt{11}\\) and direction angle equal to approximately \\(40^\circ\\)
○ magnitude of \\(\sqrt{11}\\) and direction angle equal to approximately \\(50^\circ\\)
○ magnitude of \\(\sqrt{61}\\) and direction angle equal to approximately \\(40^\circ\\)
○ magnitude of \\(\sqrt{61}\\) and direction angle equal to approximately \\(50^\circ\\)
Step1: Calculate the magnitude of the vector
The vector has components \(x = 5\) and \(y = 6\). Using the formula for the magnitude of a vector \(\vec{v}=(x,y)\), \(|\vec{v}|=\sqrt{x^{2}+y^{2}}\).
Step2: Calculate the direction angle \(\theta\)
Using the formula \(\tan\theta=\frac{y}{x}\), where \(x = 5\) and \(y = 6\). So \(\tan\theta=\frac{6}{5}=1.2\).
Then \(\theta=\arctan(1.2)\approx50^{\circ}\) (since \(\arctan(1)\approx45^{\circ}\) and \(1.2>1\))
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magnitude of \(\sqrt{61}\) and direction angle equal to approximately \(50^{\circ}\)