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review for the final solve each equation. 1) $4(6 - 8x) = -136$ 2) $-91…

Question

review for the final
solve each equation.

  1. $4(6 - 8x) = -136$
  2. $-91 = -7(1 + 6x)$
  3. $4(3n - 1) = -88$
  4. $-5(8n + 7) = -155$
  5. $8(n + 3) + 2n = 84$
  6. $-94 = 2(-5n + 4) - 7n$

solve each equation for the indicated variable.

  1. $g = ca$, for $a$
  2. $g = c + a$, for $a$

Explanation:

Response
1) Solve \( 4(6 - 8x)=-136 \)

Step1: 两边同除以4

\( \frac{4(6 - 8x)}{4}=\frac{-136}{4} \)
\( 6 - 8x=-34 \)

Step2: 移项求\(-8x\)

\( -8x=-34 - 6 \)
\( -8x=-40 \)

Step3: 两边同除以\(-8\)

\( x=\frac{-40}{-8} \)
\( x = 5 \)

Step1: 两边同除以\(-7\)

\( \frac{-91}{-7}=\frac{-7(1 + 6x)}{-7} \)
\( 13 = 1+6x \)

Step2: 移项求\(6x\)

\( 6x=13 - 1 \)
\( 6x = 12 \)

Step3: 两边同除以6

\( x=\frac{12}{6} \)
\( x = 2 \)

Step1: 两边同除以4

\( \frac{4(3n - 1)}{4}=\frac{-88}{4} \)
\( 3n - 1=-22 \)

Step2: 移项求\(3n\)

\( 3n=-22 + 1 \)
\( 3n=-21 \)

Step3: 两边同除以3

\( n=\frac{-21}{3} \)
\( n=-7 \)

Answer:

\( x = 5 \)

2) Solve \( -91=-7(1 + 6x) \)