Question

if ( b ) represents the allele for black eyes (dominant) and ( b ) represents the allele for orange eyes (recessive), what would be the genotypic ratio of a cross between a heterozygous black - eyed mendalien and an orange - eyed mendalien?
0 homozygous black (( bb )): 0 heterozygote (black) (( bb )): 1 homozygous orange (( bb ))
1 homozygous black (( bb )): 0 heterozygote (black) (( bb )): 1 homozygous orange (( bb ))
1 homozygous black (( bb )): 1 heterozygote (black) (( bb )): 1 homozygous orange (( bb ))
0 homozygous black (( bb )): 1 heterozygote (black) (( bb )): 1 homozygous orange (( bb ))
2 homozygous black (( bb )): 1 heterozygote (black) (( bb )): 1 homozygous orange (( bb ))

Explanation:

Step1: Determine the genotypes of the parents

The heterozygous black - eyed MendAlien has the genotype \(Bb\), and the orange - eyed MendAlien has the genotype \(bb\) (since orange eyes are recessive and require two recessive alleles).

Step2: Set up the Punnett square

Gametes of \(Bb\)	\(B\)	\(b\)
	\(b\)	\(Bb\)	\(bb\)

Step3: Analyze the genotypes from the Punnett square

From the Punnett square, we get two \(Bb\) (heterozygous black - eyed) and two \(bb\) (homozygous orange - eyed) genotypes. The ratio of \(Bb:bb\) is \(1:1\). There is no \(BB\) genotype as the first parent does not have a \(B\) allele to pair with another \(B\) (the second parent only has \(b\) alleles).

Answer:

0 homozygous black (\(BB\)): 1 heterozygote (black) (\(Bb\)): 1 homozygous orange (\(bb\)) (the fourth option)