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related content width meter x + 11 width x + 9 x² + 13x + 36

Question

related content
width
meter
x + 11
width
x + 9
x² + 13x + 36

Explanation:

Step1: Assume it's a rectangle, area = length × width. Given area is $x^2 + 13x + 36$ and one side (length) is $x + 9$, we need to find the width by factoring the area and dividing by the length.

First, factor the quadratic expression $x^2 + 13x + 36$. We need two numbers that multiply to 36 and add to 13. Those numbers are 4 and 9. So, $x^2 + 13x + 36=(x + 4)(x + 9)$.

Step2: Now, divide the factored area by the given length ($x + 9$) to find the width.

$\frac{(x + 4)(x + 9)}{x + 9}$ (where $x
eq - 9$ to avoid division by zero). The $(x + 9)$ terms cancel out, leaving $x + 4$.

Answer:

The width is $x + 4$ meters.