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Question
a rectangles length is 5 inches more than twice its width. its area is 50 square inches. which equation can be used to find its width, w?
2w(2w + 5) = 50
2w(w + 5) = 50
w(2w + 5) = 50
w(w + 5) = 50
Step1: Express the length in terms of width
Let the width of the rectangle be \( w \). The length is 5 inches more than twice its width, so the length \( l = 2w + 5 \).
Step2: Use the area formula for a rectangle
The area formula for a rectangle is \( A=l\times w \). Given that \( A = 50 \) square inches. Substitute \( l=2w + 5 \) into the area formula: \( w(2w + 5)=50 \).
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C. \( w(2w + 5)=50 \)