Question

a rectangle has side lengths of 2 and 48. below is the rectangle split into two small rectangles. (a) find the missing length, and then find the areas (in square units). (b) use the figure to find 2×48. 2×48 =

Explanation:

Step1: Find the missing length

The total length of the rectangle is 48 and one part is 40. So the missing length is $48 - 40=8$.

Step2: Calculate the area of the blue - colored rectangle

The area of a rectangle is length times width. For the blue - colored rectangle with length 40 and width 2, the area $A_1=40\times2 = 80$ square units.

Step3: Calculate the area of the pink - colored rectangle

For the pink - colored rectangle with length 8 and width 2, the area $A_2=8\times2=16$ square units.

Step4: Calculate 2×48

The sum of the areas of the two small rectangles is equal to the area of the large rectangle. So $2\times48=A_1 + A_2=80 + 16=96$.

Answer:

(a) Blue area: 80, Pink area: 16, Missing length: 8
(b) 96