Question

1. record the height of the drop ramp and the launch angle of the ramp you designed.

ramp height (cm) launch angle (degree)

1. predict which locations the ball will have the most potential energy and the most kinetic energy. explain your reasoning.

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Explanation:

For potential energy, the formula is $PE = mgh$ (mass × gravity × height). Higher height means more PE, so the ball has the most potential energy at the highest point of the drop ramp (top of the ramp) because height ($h$) is maximum there. For kinetic energy, $KE=\frac{1}{2}mv^{2}$ (½ mass × velocity squared). As the ball moves down the ramp, potential energy converts to kinetic energy, so velocity ($v$) is highest at the lowest point (launch end of the ramp), giving the most kinetic energy there (since velocity is maximum when height is minimum, assuming no energy loss).

Answer:

• Most Potential Energy: At the top of the drop ramp (highest height, so \( PE = mgh \) is maximized as \( h \) is largest).
• Most Kinetic Energy: At the launch end of the ramp (lowest height, where potential energy has converted most to kinetic energy, so \( KE=\frac{1}{2}mv^{2} \) is maximized as \( v \) is largest).