Question

in a recent harris poll, a random sample of adult americans (18 years and older) was asked, \when you see an ad emphasizing that a product is made in america, are you more likely to buy it, less likely to buy it, or neither more nor less likely to buy it?\ a subset of the results of the survey, by age group, are presented in the accompanying contingency table. using the results of the survey, complete parts (a) through (c).
the probability is approximately 0.264
(round to three decimal places as needed.)
(b) what is the probability that a randomly selected individual is neither more nor less likely to buy a product emphasized as \made in america,\ given the individual is 35 to 44 years of age?
the probability is approximately 0.376
(round to three decimal places as needed.)
(c) are 18 - to 34 - year - olds more likely to buy a product emphasized as \made in america\ than individuals in general?
because the probability that a randomly selected 18 - to 34 - year - old is more likely to buy a product emphasized as \made in america,\ , is the probability that a randomly selected individual is more likely to buy a product emphasized as \made in america,\ .
(round to three decimal places as needed.)

Explanation:

Step1: Calculate the probability for 18 - 34 - year - olds

The formula for probability is \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). For 18 - 34 - year - olds, the number of favorable outcomes (more likely) is \(n_1 = 234\), and the total number of 18 - 34 - year - olds is \(N_1=537\). So \(P_1=\frac{234}{537}\approx0.436\)

Step2: Calculate the probability for all individuals

For all individuals, the number of favorable outcomes (more likely) is \(n_2 = 1322\), and the total number of individuals is \(N_2 = 2146\). So \(P_2=\frac{1322}{2146}\approx0.616\)

Answer:

Since \(0.436<0.616\), 18 - to 34 - year - olds are less likely to buy a product emphasized as "Made in America" than individuals in general.