Question

read the story.
the teeny greens miniature golf course is holding a contest where anyone who gets a hole - in - one on at least 3 holes wins a free month of mini - golf. devin gets a hole - in - one 5% of the time. how likely is it that devin will get at least 3 holes - in - one on the first 9 holes he plays during todays game?
devin simulates the situation by using a computer to randomly generate 9 numbers from 1 to 20. each time a 1 appears, it represents a hole - in - one.
this table shows the results of 500 trials:
based on devins results, what is the probability that he will get at least 3 holes - in - one?
%

Explanation:

Step1: Understand the meaning of "at least 3"

"At least 3" means 3 or more. From the table, the number of trials with 3 holes - in - one is 5, and the number of trials with 4, 5, 6, 7, 8, 9 holes - in - one is 0.

Step2: Calculate the probability

The formula for probability \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). The number of favorable outcomes (at least 3 holes - in - one) is \(5 + 0+0+0+0+0+0 = 5\). The total number of outcomes is \(500\). So \(P=\frac{5}{500}\).

Step3: Simplify the fraction to a percentage

\(\frac{5}{500}=\frac{5\div5}{500\div5}=\frac{1}{100}=1\%\)

Answer:

\(1\%\)