Question

if a ray qt bisects ∠rqs, what would be the measure of one of the resulting angles? measure =

Explanation:

Step1: Use angle - bisector property

Since ray $QT$ bisects $\angle RQS$, we have $3x + 5=x + 3$.

Step2: Solve the equation for $x$

Subtract $x$ from both sides: $3x - x+5=x - x + 3$, which simplifies to $2x+5 = 3$. Then subtract 5 from both sides: $2x+5 - 5=3 - 5$, so $2x=-2$. Divide both sides by 2: $x=-1$.

Step3: Find the measure of one of the resulting angles

Substitute $x = - 1$ into the expression for one of the angles, say $x + 3$. Then the measure of the angle is $-1+3=2^{\circ}$.

Answer:

$2$