Question

a random sample of n = 1675 internet users in the us found that 469 of them have customized their web browsers home page to include news from sources and on topics that particularly interest them. find the standard error of proportion(sep), rounded to 2 decimal places? 0.08 0.01 0.04 0.02

Explanation:

Step1: Calculate sample proportion

The sample proportion $\hat{p}=\frac{x}{n}$, where $x = 469$ and $n=1675$. So, $\hat{p}=\frac{469}{1675}\approx0.28$.

Step2: Calculate standard error of proportion

The formula for the standard error of proportion is $SEP=\sqrt{\frac{\hat{p}(1 - \hat{p})}{n}}$. Substitute $\hat{p}=0.28$ and $n = 1675$ into the formula:

$$
LATEXBLOCK0
$$

Answer:

0.01