Question

a racehorse is running at 42 miles per hour, equivalent to 18.8 meters per second. the horse and its jockey have a combined mass of 520 kilograms. how much kinetic energy do they have?
$ke = \frac{1}{2}mv^{2}$
(1 point)
451,584.0 j
90,480.6 j
458,640 j
91,894.4 j

Explanation:

Step1: Substitute the values into the formula

Given \(m = 520\space kg\) and \(v=18.8\space m/s\), substitute into \(KE=\frac{1}{2}mv^{2}\).
So, \(KE=\frac{1}{2}\times520\times(18.8)^{2}\)

Step2: Calculate \((18.8)^{2}\)

\((18.8)^{2}=18.8\times18.8 = 353.44\)

Step3: Calculate \(\frac{1}{2}\times520\)

\(\frac{1}{2}\times520 = 260\)

Step4: Multiply the results

\(KE=260\times353.44\)
\(KE = 91894.4\space J\)

Answer:

91,894.4 J