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Question
quiz 7.2.1 - rational exponent properties
simplify
$x^{-3}x^{2}y^{\frac{-1}{2}}$
\\(\circ\\) a. \\(\dfrac{1}{xy^{\frac{1}{2}}}\\)
\\(\circ\\) b. \\(\dfrac{x^{5}}{y^{\frac{1}{2}}}\\)
\\(\circ\\) c. \\(xy^{\frac{1}{2}}\\)
\\(\circ\\) d. \\(\dfrac{1}{x^{6}y^{\frac{1}{2}}}\\)
Step1: Combine like x terms
When multiplying terms with the same base, add exponents: $x^{-3} \times x^{2} = x^{-3+2} = x^{-1}$
Step2: Rewrite negative exponent
A negative exponent means reciprocal: $x^{-1} = \frac{1}{x}$
Step3: Combine with y term
Keep the $y^{-\frac{1}{2}}$ term, rewrite it as $\frac{1}{y^{\frac{1}{2}}}$, then multiply: $\frac{1}{x} \times \frac{1}{y^{\frac{1}{2}}} = \frac{1}{xy^{\frac{1}{2}}}$
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a. $\frac{1}{xy^{\frac{1}{2}}}$