Question

question
what is the volume of a hemisphere with a radius of 61.9 m, rounded to the nearest tenth of a cubic meter?
answer attempt 2 out of 2
m³
submit answer
show examples

Explanation:

Step1: Recall the formula for the volume of a hemisphere

The volume \( V \) of a hemisphere is given by the formula \( V = \frac{2}{3}\pi r^3 \), where \( r \) is the radius of the hemisphere.

Step2: Substitute the given radius into the formula

We are given that the radius \( r = 61.9 \) m. Substituting this into the formula, we get:

$$ V=\frac{2}{3}\pi(61.9)^3 $$

First, calculate \( (61.9)^3 \):

$$ 61.9^3 = 61.9\times61.9\times61.9 = 61.9\times 3831.61=237176.659 $$

Then, multiply by \( \frac{2}{3}\pi \):

$$ V=\frac{2}{3}\times\pi\times237176.659 $$

$$ V=\frac{474353.318}{3}\times\pi $$

$$ V = 158117.7727\times\pi $$

Using \( \pi\approx3.14159 \):

$$ V\approx158117.7727\times3.14159 $$

$$ V\approx496654.4 $$

Answer:

\( 496654.4 \)