Question

question
what is the volume of a cylinder with a height of 18.6 in and a base with a radius of 6.2 in, to the nearest tenth of a cubic inch?
answer attempt 1 out of 2

Explanation:

Step1: Write the formula for the volume of a cylinder

The formula for the volume of a cylinder is \(V=\pi r^{2}h\), where \(r\) is the radius and \(h\) is the height.

Step2: Substitute the given values into the formula

Given \(r = 6.2\) in and \(h=18.6\) in. Substitute into the formula: \(V=\pi\times(6.2)^{2}\times18.6\).
First, calculate \((6.2)^{2}=6.2\times6.2 = 38.44\).
Then, \(V=\pi\times38.44\times18.6\).
\(38.44\times18.6=(40 - 1.56)\times18.6=40\times18.6-1.56\times18.6=744-29.016 = 714.984\).
So \(V=\pi\times714.984\).
Taking \(\pi\approx3.14\), then \(V\approx3.14\times714.984\).
\(3.14\times714.984=(3 + 0.14)\times714.984=3\times714.984+0.14\times714.984=2144.952+100.09776 = 2245.04976\).

Answer:

\(2245.0\)