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Question
question
solve the system of equations graphed on the coordinate axes below.
( y = -x - 8 )
( y = \frac{1}{3}x - 4 )
Step1: Set the equations equal
Since both equations are solved for \( y \), set \( -x - 8=\frac{1}{3}x - 4 \).
Step2: Add \( x \) to both sides
\( -8=\frac{1}{3}x+x - 4 \), simplify \( \frac{1}{3}x+x=\frac{4}{3}x \), so \( -8=\frac{4}{3}x - 4 \).
Step3: Add 4 to both sides
\( -8 + 4=\frac{4}{3}x \), which gives \( -4=\frac{4}{3}x \).
Step4: Solve for \( x \)
Multiply both sides by \( \frac{3}{4} \): \( x=-4\times\frac{3}{4}=-3 \).
Step5: Substitute \( x \) into one equation
Use \( y=-x - 8 \), substitute \( x = - 3 \): \( y=-(-3)-8=3 - 8=-5 \).
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The solution is \( (-3, -5) \)