Question

question
solve the following inequality for a. write your answer in simplest form.
-10a - 6 ≤ -7a + 10

Explanation:

Step1: Add $10a$ to both sides

$-10a - 6 + 10a \leqslant -7a + 10 + 10a$
$-6 \leqslant 3a + 10$

Step2: Subtract 10 from both sides

$-6 - 10 \leqslant 3a + 10 - 10$
$-16 \leqslant 3a$

Step3: Divide by 3 on both sides

$\frac{-16}{3} \leqslant \frac{3a}{3}$
$\frac{-16}{3} \leqslant a$

Answer:

$a \geqslant -\frac{16}{3}$