Question

question
simplify the expression below using order of operations.
\\(\frac{-10 + (-7)}{8 + (-3)^2}-\frac{-8 + 8}{-10 + 2}\\)

Explanation:

Step1: Calculate numerators and denominators separately

First, calculate the numerator and denominator of the first - fraction:
For the numerator of the first fraction: $-10+(-7)=-10 - 7=-17$.
For the denominator of the first fraction: $8+(-3)^2=8 + 9 = 17$.
For the numerator of the second fraction: $-8 + 8=0$.
For the denominator of the second fraction: $-10 + 2=-8$.
The expression becomes $\frac{-17}{17}-\frac{0}{-8}$.

Step2: Simplify each fraction

Simplify $\frac{-17}{17}=-1$ and $\frac{0}{-8}=0$.
The expression is now $-1-0$.

Step3: Subtract

$-1-0=-1$.

Answer:

$-1$