Question

question
a side of the triangle below has been extended to form an exterior angle of 163°. find the value of x.
163° x° 51°

Explanation:

Step1: Use the exterior angle property

The exterior angle of a triangle is equal to the sum of the two non - adjacent interior angles. Let the non - adjacent interior angles be \(x\) and \(51^{\circ}\), and the exterior angle is \(163^{\circ}\). So, \(x + 51^{\circ}=163^{\circ}\).

Step2: Solve for \(x\)

Subtract \(51^{\circ}\) from both sides of the equation \(x+51^{\circ}=163^{\circ}\).
\(x = 163^{\circ}-51^{\circ}\)
\(x = 112^{\circ}\)

Answer:

\(112\)