Question

question 4
5 pts

what is the output of the following code?

java
import java.io.*;
public class loop
{
public static void main (string args) throws ioexception
{
for(int i = 0; i < 2; i++)
{
for(int j = 0; j < 3; j++)
{
if(i == j)
{
continue;
}
system.out.println(\i = \ + i + \ j = \ + j);
}
}
}
}

a)
i=1 j=1
i=1 j=2
i=1 j=0
i=2 j=2

b)
i=0 j=1
i=0 j=2
i=1 j=0
i=1 j=2

c)
i=0 j=0
i=1 j=1
i=1 j=1
i=2 j=2

o a
o b
o c

Explanation:

🆕 New Concept Discovered: Nested Loops with Control Statements
How loops inside loops behave when using control statements like continue.

Step 1: Understand the Loop Structures

The code contains a nested loop structure:

• Outer loop: for(int i = 0; i < 2; i++) runs for \( i = 0 \) and \( i = 1 \).
• Inner loop: for(int j = 0; j < 3; j++) runs for \( j = 0 \), \( j = 1 \), and \( j = 2 \) during each iteration of the outer loop.

Inside the inner loop, there is a conditional check:

if (i == j) {
    continue;
}

The continue statement immediately skips the rest of the current iteration of the inner loop and moves to the next update expression (j++).

---

Step 2: Trace the Execution for \( i = 0 \)

When the outer loop starts, \( i = 0 \). We enter the inner loop:

• \( j = 0 \):
• Check condition: \( i == j \) \(

ightarrow\) \( 0 == 0 \) is true.

• Action: The continue statement executes. The print statement is skipped.
• \( j = 1 \):
• Check condition: \( i == j \) \(

ightarrow\) \( 0 == 1 \) is false.

• Action: The print statement executes:

i = 0 j = 1

• \( j = 2 \):
• Check condition: \( i == j \) \(

ightarrow\) \( 0 == 2 \) is false.

• Action: The print statement executes:

i = 0 j = 2

---

Step 3: Trace the Execution for \( i = 1 \)

The outer loop increments to \( i = 1 \). We enter the inner loop again:

• \( j = 0 \):
• Check condition: \( i == j \) \(

ightarrow\) \( 1 == 0 \) is false.

• Action: The print statement executes:

i = 1 j = 0

• \( j = 1 \):
• Check condition: \( i == j \) \(

ightarrow\) \( 1 == 1 \) is true.

• Action: The continue statement executes. The print statement is skipped.
• \( j = 2 \):
• Check condition: \( i == j \) \(

ightarrow\) \( 1 == 2 \) is false.

• Action: The print statement executes:

i = 1 j = 2

---

Step 4: Compare with Given Options

Let's compile the printed lines in order:

i = 0 j = 1
i = 0 j = 2
i = 1 j = 0
i = 1 j = 2

This matches option b exactly.

Answer:

b