Question

question 2
1 pts
the normal force that acts on objects on ramps is equal to....
mg cos (theta)
mg sin (theta)
mg tan (theta)
mg
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Explanation:

Step1: Analyze the forces on an object on a ramp

When an object of mass \(m\) is on a ramp inclined at an angle \(\theta\) with the horizontal, the gravitational force \(F = mg\) acts vertically downwards. We resolve this force into two components: one parallel to the ramp (\(mg\sin\theta\)) and one perpendicular to the ramp (\(mg\cos\theta\)).

Step2: Determine the normal force

The normal force \(N\) acts perpendicular to the surface of the ramp. Since there is no acceleration in the direction perpendicular to the ramp (assuming the object is in equilibrium or moving along the ramp), the normal force balances the component of the gravitational force perpendicular to the ramp. So, \(N=mg\cos\theta\).

Answer:

\(mg\cos(\text{theta})\)