Question

question 1
1 pts
given two similar triangles, \\( \triangle a b c \sim \triangle d e f \\), where, \\( a = 4 \\),
\\( c = 6, d = 2 \\), find \\( f \\).

Explanation:

Step1: Use the property of similar triangles

For similar triangles \(\triangle ABC\sim\triangle DEF\), the ratios of corresponding sides are equal. That is \(\frac{a}{d}=\frac{c}{f}\).

Step2: Substitute the given values

We know \(a = 4\), \(c = 6\), \(d=2\). Substituting into \(\frac{a}{d}=\frac{c}{f}\), we get \(\frac{4}{2}=\frac{6}{f}\).

Step3: Solve for \(f\)

Cross - multiply: \(4f=2\times6\). Then \(4f = 12\), and \(f=\frac{12}{4}=3\).

Answer:

\(3\)