question 6
3 pts
in a game, 4 bingo balls are being picked randomly from a pool of 59 bingo numbers.
assuming that the order of the numbers that are picked does not matter, how many possible
ways are there for picking the numbers.

Question

Accepted Answer

# Explanation:
## Step1: Recall combination formula
The combination formula is $C(n,r)=\frac{n!}{r!(n - r)!}$, where $n = 59$ (total number of bingo numbers) and $r=4$ (number of balls picked).
## Step2: Calculate factorial values
$$
\begin{align*}
n!&=59!\
r!&=4! = 4\times3\times2\times1=24\
(n - r)!&=(59 - 4)!=55!
\end{align*}
$$
## Step3: Substitute into combination formula
$$
\begin{align*}
C(59,4)&=\frac{59!}{4!(59 - 4)!}\
&=\frac{59\times58\times57\times56\times55!}{24\times55!}\
&=\frac{59\times58\times57\times56}{24}
\end{align*}
$$
## Step4: Simplify the expression
$$
\begin{align*}
\frac{59\times58\times57\times56}{24}&=\frac{59\times58\times57\times56}{24}\
&=59\times58\times57\times\frac{56}{24}\
&=59\times58\times57\times\frac{7}{3}\
&=59\times58\times19\times7\
&=(59\times58)\times(19\times7)\
&=3422\times133\
& = 455126
\end{align*}
$$

# Answer:
$455126$

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QUESTION IMAGE

Question

Explanation:

Step1: Recall combination formula

Step2: Calculate factorial values

Step3: Substitute into combination formula

Step4: Simplify the expression

Answer: